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9v^2+29v=0
a = 9; b = 29; c = 0;
Δ = b2-4ac
Δ = 292-4·9·0
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{841}=29$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-29}{2*9}=\frac{-58}{18} =-3+2/9 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+29}{2*9}=\frac{0}{18} =0 $
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